@Tony,

What kind of error are you getting? What is the message, type, stack trace?

Are you sure that there exists a file at the location you specify?
You can use File.Exists to check.

Also there is no MailBuilder.AddAttachment overload that takes StringBuilder class as a parameter, did you meant:
builder.AddAttachment(tempFileName.ToString())?

I have an app that I am creating (C#, XAML). I have a .csv file that my app created and stores it in the following location:

StringBuilder tempFileName = new StringBuilder();
tempFileName.Append(ApplicationData.Current.LocalSettings.Values[“lastName”].ToString()).Append(“_”)
.Append(ApplicationData.Current.LocalSettings.Values[“firstName”].ToString()).Append(” – (“)
.Append(txtEventName.Text).Append(“).csv”);

Then I tried to attach this file to the email:
MimeData attachment = builder.AddAttachment(tempFileName);
attachment.ContentType = ContentType.TextPlain;

It is giving me an error. What am I doing wrong. I looked at the sample and did exactly what it says.

Thank you.

You can catch the exception thrown by Connect method.

Peter,

As you might expect there is no direct conversion method.
You need to have data as byte array, ContentType object (you can parse it from string) and file name:

byte[] data = ...;
string contentType = ...;
string fileName = ...;

MimeData mime = new MimeFactory().CreateMimeData();
mime.Data = data;
mime.ContentType = ContentType.Parse(contentType);
mime.FileName = fileName;

ContentStream = Stream object.
Filename = String object.
ContentType = String object.

-Peter Steiness
NOVAQ – Qmanager.dk licens.